cup\" calorimeter, or constant pressure calorimeter, is frequently used to deter
ID: 1034916 • Letter: C
Question
cup" calorimeter, or constant pressure calorimeter, is frequently used to determine Therminiser the specific heat of a solid, or to measure the energy of a solution phase reaction. Seering rod Since the cup itself can absor b energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant One way to do this is to use a common metal of known heat capacity. In the laboratory a student heats 96.22 measures the final temperature to be 29.05°C Using the accepted value for the specific heat of copper (See the References tool), calculate the calorimeten grams of copper to 99.4S oC and then drops it into a cup containing 78.06 grams of water at 21.10 °C. She Metal constant Calorimeter Constant J/oCExplanation / Answer
Heat absorbed by water (qwater) = mass of water x specific heat of water x temperature change
= 78.06 g x (4.184 J/g oC) x ( 29.02 oC - 21.10 oC)
= 2587 J
Heat absorbed by calorimeter (qcal) = calorimeter constant (Ccal) x temperature change
= Ccal x (29.02 oC - 21.10 oC)
= Ccal x 7.92 oC
Heat lost by metal (qmetal) = mass of copper x specific heat of copper x temperature change
= 96.22 g x (0.385 J/g oC) x (99.48oC - 29.05oC)
= 2609 J
Since heat gained is equal to heat lost,
qwater + qcal = qmetal
2587 J + ( Ccal x 7.92 oC) = 2609 J
Ccal x 7.92 oC = 2609 J - 2587 J = 22 J
Ccal = (22 J/ 7.92 oC) = 2.78 J/oC.
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