A sample of 1.25 g of CaCO3 is decomposed by heating according to.... #28 41 -1

Question

A sample of 1.25 g of CaCO3 is decomposed by heating according to....
#28

41 -1 27 0.5865 g sample of lactic acid (HC,H,O,) is burned in a calorimeter whose heat capacity is 4812 kl C. The temperature increases from 23.10 c to 24.95°c Calculate the heat of combustion of lactic acid a. per gram b. per mole 28. A sample of 1.25 g ofcaco, is decomposed by heating according to: Caco, (s) ? CO2 (g) + CaO (s) How many milliliters of CO2 will evolve at 740 torr and 25 C? ANSWERS 2. b 3. b 5. d 6. d 7. d 8. c 9, ? 10. c 12. d 13. a 14. d 5. c 7. d 8. b 0. b

Explanation / Answer

In this reaction one mole CaCO3 produce one mole CO2.

1.25 gm CaCO3 = mass / molar mass = 1.25 / 100 = 0.0125 mole.

so moles of CO2 produce = 0.0125 mole.

ideal gas equation is

PV = nRT

(740 / 760) * V = 0.0125 * 0.0821 * 298

V = 0.314 L = 314 ml

so volume of CO2 produced = 314 ml.

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