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Search Textbook Solutio ing.com/ibiscms/mod/ibis/view.php?id-4078479 una página, arrástrala a esta barra de marcadores. Importar marcadores ahora... Jump to Periodic Table Map Sapling Learning The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCOs) reacting with one mole of hydrochloric acid (HCI) to produce one mole of carbonic acid (H-CO,) and one mole of sodium chloride (NaCI). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 4 mol of NaHCOs and 7 mol of HCL Number 4mol H,Co, Which of the two reactants limits the number of moles of H CO, that can be made? How much excess reactant remains after the reaction? Number NaHCO mol There is additional feedback avalable View this feedback bottom dvider bar on the on the dvider Incorret bar again to hide the adcitional feedback Close @o_ Up & Vinw Solaion #Try AganNexl

Explanation / Answer

NaHCO3 + HCl - - - >NaCl + H2CO3

1 : 1 : 1 : 1

Here, 4NaHCO3 + 7 HCl - - - - - > 4NaCl + 4HCl

And 3 moles of HCl will be left without reacting.

The limiting reagent or the reactant consumed completely is NaHCO3 or sodium carbonate.

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