A Total Acid Content Trial 1 0.44% Trial 2 0,44% Trial 3 0,4s Trial 1Trial 2Tria

Question

A Total Acid Content Trial 1 0.44% Trial 2 0,44% Trial 3 0,4s Trial 1Trial 2Trial 3 Mass of Aspirin tablet (g): NaOH nitial Burette Reading -Orn) ?gnLloanL Final Burette Reading 12amLI/5mLIM:nL Volume of NaOH L mL 24mL Assuming that there are no acid impurties in the Aspirin tablet, use your titration data from Part A, determine the mass of ASA in each of the tablets, Include a sample calculation for 1 of the trials. (Not since the tablets are different you can't average your titration values). in O Trail 1 Trial 2Trial3 ASA Content (g)

Explanation / Answer

Aspirin also known as acetyl salicylic acid (ASA) when titrated with NaOH, the following reaction occurs:

CH3COOC6H4COOH (aq) + NaOH (aq) -----------------> CH3COOC6H4COONa (aq) + H2O (l)

For every 1 mole of CH3COOC6H4COOH, 1 mole of NaOH is used.

Sicne molarity and volume of NaOH ar given, moles of NaOH Can be calcuated:

For trial 1:

Moles of NaOH = Molarity of NaOH M (moles/L) x Volume of NaOH (in L)

Moles of NaOH = 0.10 (moles/L) x 20.0 x 10-3 L = 2.00 x 10-3 moles

Moles NaOH = Moles Acetyl salicylic acid = 2.00 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = molar mass of salicylic acid (g/mol) x moles of ASA

= 180.16 g/mol * 2.00 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = 360.32 x 10-3 g = 0.360 g

For trial 2:

Moles of NaOH = Molarity of NaOH M (moles/L) x Volume of NaOH (in L)

Moles of NaOH = 0.10 (moles/L) x 18.0 x 10-3 L = 1.80 x 10-3 moles

Moles NaOH = Moles Acetyl salicylic acid = 1.80 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = molar mass of salicylic acid (g/mol) x moles of ASA

= 180.16 g/mol * 1.80 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = 324.3 x 10-3 g = 0.324 g

For trial 3:

Moles of NaOH = Molarity of NaOH M (moles/L) x Volume of NaOH (in L)

Moles of NaOH = 0.10 (moles/L) x 24.0 x 10-3 L = 2.40 x 10-3 moles

Moles NaOH = Moles Acetyl salicylic acid = 2.40 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = molar mass of salicylic acid (g/mol) x moles of ASA

= 180.16 g/mol * 2.40 x 10-3 moles

Mass of acetyl salicylic acid (ASA) = 432.38 x 10-3 g = 0.432 g

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