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iPad ??5:02 cvg.cengagenow.com ???? Bing Google Yahoo ???? Chegg.com ????-?????1? oWLv2 | Online teaching and learn... CH 18 ELECTROCHEM TEST 1 pt Use the References to access important values if needed for this question Question 1 Question 2 Question 3 Question 4 Question 5 Use the standard reduction potentials located in the Tables' linked above to calculate the standard free energy change in kJ for the reaction: 1 pt 2H (aq) Fe(s) H2(g)+Fe (aq) 1 pt Answer kJ K for this reaction would bethan one. Question 9 1 pt Submit Answer Try Another Version Question 10 9 item attempts remaining 1 pt 1 pt 1 pt 1pt 1 pt 1 pt 1 pt Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Question 17 Question 18 0 Progress: 8/18 items Due Mar 26 at 11:55 PM Previous Next Finish Assignment Email Instructor Save and Exit Cengage Learning |Cengage Technical Support

Explanation / Answer

Given that, 2H+(aq) + Fe(s) ----> H2(g) + Fe^2+(aq)

In the above reaction, oxidation half reaction is Fe(s) -----> Fe^2+(aq) + 2e-; Ered = -0.44 V

reduction half reaction is, 2H+(aq) + 2e- -----> H2(g); Ered = 0.0 V

Eo cell = Ecathode - Eanode = 0.0 V - (-0.44V) = 0.44 V

Standard free energy is given by

dGo = -nFEocell = -2 x 96.5 KJ/mol.V x 0.44 V = -84.92 KJ

dG = -RTlnK

SInce dG is -ve, K would be greater than 1

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