H16HW 03r26/18 10 Question (4 points) a See page 816 A basic solution contains t
ID: 1032484 • Letter: H
Question
H16HW 03r26/18 10 Question (4 points) a See page 816 A basic solution contains the lodide and phosphate ions that are to be separated via selective precipitation Thercocentration, which is 970×10 s M is 10,000 times less than that of the PO-in ato.970M A solution containing the silver(l) ion is slowly added.Answer the questions below Kp of Agl is 8.30-10 17 and of Ag POs8.90x101 1st attempt Part 1 (1 point) i See Periodic Table See Hint Calculate the minimum Ags" concentration required to cause precipitation of Agl mol /L 1017> O PExplanation / Answer
Selective precipitation
Part 1.
minimum [Ag+] needed to precipitate AgI
= Ksp/[I-]
= 8.3 x 10^-17/9.7 x 10^-5
= 8.56 x 10^-13 M
Part 2,
minimum [Ag+] needed to precipitate Ag3PO4
= cube rt(Ksp/[PO4^3-])
= cube rt(8.9 x 10^-17/0.970)
= 4.51 x 10^-6 M
Part 3,
salt to precipitate first is the one with lowest Ksp value,
AgI
Part 4,
[I-] when Ag3PO4 begins to precipitate = 8.3 x 10^-17/4.51 x 10^-6 = 1.84 x 10^-11 M
amount [I-] remained in solution = (1.84 x 10^-11) x 100/9.7 x 10^-5 = 1.89 x 10^-5%
so amunt [I-] precipitated = almost 100% (quantitative)
So,
Is the separation of the remaining ion less than 0.10%,
Yes
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