ingChemistry:ChaptelTu ingChemistry Chapte Tonedy | https://session.masteringche

Question

ingChemistry:ChaptelTu ingChemistry Chapte Tonedy | https://session.masteringchemistry.com/myct/itemView?assignmentProblemID apter 16 Ready-To-Go Teaching Module After Class: Determining [H30+] and Practice 16.7 -Enhanced - with Feedback re ou may want to reference (Pages 700- 709) Section 16.7 while completing this problem. PartA Find the pH of a 0.013 Msolution of HP (The value of Ka for HF is 3.5 × 10 4 Express your answer using two decimal places. pH- Submit Incorrect; Try Again; 4 attempts remaining When setting up the equilibrium expression for K, in which a represents IL:O should use a more precise method, specifically the quadratic formula, to cafcufate the

Explanation / Answer

Ka at equillibrium = [H+] [F-] / [HF]

Let x M of H+ and F- is present at the equillibrium , so putting all the values we get :

= 3.5 x 10-4= (x) (x) / (0.013 - x)

= (0.0455 * 10-4) - (3.5x * 10-4) = x2

= x2 + (3.5x*10-4) - (0.0455 *10-4) = 0

x = 0.00196

pH = -log [H+]

pH = -log(0.00196)

= 2.7

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