Experiment 2: Synthesize Copper Oxide from Copper (II) Sulfate Pentahydrate Lab

ID: 1031496 • Letter: E

Question

Experiment 2: Synthesize Copper Oxide from Copper (II) Sulfate Pentahydrate Lab Results Record the following results in the table below.

mass of empty beaker 85.000 g

mass of beaker and copper (II) sulfate pentahydrate 90.000 g

mass of empty test tube 27.400 g

mass of test tube after heating and cooling 29.267 g

Data Analysis

A. How many moles of copper were in the copper oxide formed?

The molar mass of copper (II) sulfate pentahydrate is 249.68 g/mol. For best accuracy, use the mass measurements read using the balance.

B. Calculate the mass of oxygen in the copper oxide. The molar mass of copper is 63.55 g/mol and the molar mass of oxygen is 16.00 g/mol

C. Calculate the number of moles of oxygen in the copper oxide. The molar mass of oxygen is 16.00 g/mol.

D. Calculate the molar ratio between copper and oxygen.

ans)

Mass of Copper (II) sulphate pentahydrate = 90.000 - 85.000 g = 5 g

Molar mass of Copper (II) sulphate pentahydrate = 249.68 g/mol

Moles of Copper (II) sulphate pentahydrate = 5 / 249.68 = 0.02002 moles.

Mass of Copper (II) sulphate = 249.68 - 90 = 159.68 g

Mass of Copper = 63.55 g

Molar Mass of Copper Oxide = 63.55 + 16 = 79.55 g

Mass of Copper Oxide = 29.267 - 27.400 = 1.867 g

Moles of copper oxide formed = 1.867 / 79.55 = 0.0234

Mass of Copper in the Copper Oxide = (63.55/79.55)*1.867 = 1.491 g

Mass of Oxygen in the Copper Oxide = 1.867-1.491 = 0.376 g

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