experiment: the synthesis of aluminum 60 DATA SHEET A. NAME 1. Mass of aluminum

Question

experiment: the synthesis of aluminum

60 DATA SHEET A. NAME 1. Mass of aluminum used: -grams 2. Mass of vial used to weigh your product: grams 3. Mass of vial or filter paper+product (alum): ms 4. Actual yield of alum: rams (Line 3-Line 2) 5. Calculate the moles of aluminum used in the experiment. Show how you arrived at your answer 6. Calculate the theoretical yield of alum. Explain how you arrived at your answer grams a 2301mol Al x 20.93153 A 7. Calculate your percentage yield of alum. Show how you arrived at your answer. 5.460 DATA SHEET B. Record the observations for Procedure B here 1-Litrnos Paper turned puochY toned 2. added uhite when bso The flame was red m n

Explanation / Answer

Preparation of alum

1. mass of Al used = 0.5 g

moles Al = 0.5 g/27 g/mol = 0.0185 moles

4. actual mass of alum obtained = 5.48 g

5. moles Al used in reaction = 5.48 g x 27 g/mol/474.4 g/mol = 0.01155 moles

6. theoretical yield of alum = 0.0185 mol x 474.4 g/mol = 8.78 g

7. percent yield of alum = 5.48 x 100/8.78 = 62.43%

In conclusion we have prepared alum starting with Al. The percent yield was found to be 62.43%. The possible sources of error in the experiment may arise from loss of material while transferring from beaker to the filter paper. Insufficient time gives for Al to react and form Alum.

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