determine volume of hydrogen gas (in liters) that will be produced when 2.43 g o
ID: 1030834 • Letter: D
Question
determine volume of hydrogen gas (in liters) that will be produced when 2.43 g of magnesium is placed into excess hydrochloric acid in the following chemical reaction. The reaction is performed at a constant temp of 309K and constant pressure of .860atm
Mg (s) + 2HCl (aq) —> MgCl2 (aq) + H2 (g)
determine volume of hydrogen gas (in liters) that will be produced when 2.43 g of magnesium is placed into excess hydrochloric acid in the following chemical reaction. The reaction is performed at a constant temp of 309K and constant pressure of .860atm
Mg (s) + 2HCl (aq) —> MgCl2 (aq) + H2 (g)
determine volume of hydrogen gas (in liters) that will be produced when 2.43 g of magnesium is placed into excess hydrochloric acid in the following chemical reaction. The reaction is performed at a constant temp of 309K and constant pressure of .860atm
Mg (s) + 2HCl (aq) —> MgCl2 (aq) + H2 (g)
determine volume of hydrogen gas (in liters) that will be produced when 2.43 g of magnesium is placed into excess hydrochloric acid in the following chemical reaction. The reaction is performed at a constant temp of 309K and constant pressure of .860atm
Mg (s) + 2HCl (aq) —> MgCl2 (aq) + H2 (g)
Explanation / Answer
No. of moles of Mg = 2.43 g / 24.3 g mol-1 = 0.1 mol
From the balanced equation, one mole of Mg produces one mole of H2. So 0.1 mol Mg produces 0.1 mol of H2
PV = nRT
V = nRT / P
V = 0.1 mol x 0.0821 L atm K-1 mol-1 x 309 K / 0.860 atm
Volume of H2 produced, V = 2.95 L
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