the highest voltage. What is the cell notation for this voltaic cell. Note: I’m

Question

the highest voltage. What is the cell notation for this voltaic cell. Note: I’m not sure if I should include the NO3 from the salt bridge in the notation.
2. Write the balanced heals cell reaction for this voltaic cell and calculate the expected voltage
3. Separate question but: why would voltage increase when ammonia was added to a 0.001M cu2+ cell. A bit of context is nh3 takes cu out of solution which increases gradient and increases voltage. Is there a more in-depth explanation and what exactly is an increased gradient? value for the half-cell potential for zine tw uelu Zn(s) Zn2 (aq)+ 2e + Cu (aq)+2e Cu(s) Zn(s)+ Cu2(aq) Zn2 (a) + Cu(s) E half-cell -0.7628 V E half-cell -0.3402 V E cell 1.1030 v n this manner we can determine the relative cell potentials for any series of half-cells, hose given in Table 5-1: E° (V) 0.80 0.77 0.34 Half-reaction Ag (aq) e Ag(s) Fe (aq) + leFe2 (aq) Cu (aq)+2e Cu(s) 2H (aq) + 2e H2(g) Pb (aq)+ 2e Pb(s) Ni (aq) +2e - Ni(s) Cd(aq) +2e Cd(s) Fe? (aq) +2e Fe(s) 0.00 -0.13 0.25 0.40 0.44 Zn2 (aq) +2e Zn(s) 0.76 5-1: Half-cell potentials. otentials are tabulated as reduction potentials. Standard reduction rements taken in the standard state, i.e. 1 M concentrations for all ions, 2 re for all gases.

Explanation / Answer

1) In an electrochemical cell , anode is the electrode at which oxidation half reaction occur and cathode is the electrode at which reduction takes place. The potential of the cell is E = Ecathode - Eanode. you can use the half cell reaction given here and their combination can give the highest voltage cell. for this take the electrode with largest positve value and largest negative value, which can possibly give largest voltage for the cell. Here take

Fe3+(Aq) + 1 e- gives Fe2+ ( 0.77 V)

Zn2+(Aq) + 2 e- gives Zn (s) (-0.76 V)

So Ecell will be = 0.77 + 0.76 = 1.53 V

salt bridge does not take part in the chemical reaction.

2) 2 Fe2+(Aq) gives 2 Fe2+ + 2 e- (oxidation half cell reaction)

Zn2+(Aq) + 2 e- Gives Zn(s) ( reduction half reaction)

The expected voltage of this cell is

Ecell = 0.77 + 0.76 = 1.53 V

3) whwn ammonia is added to the coper electrolyte an insoluble compound copper (II) Hydroxide di hydrate is formed .and it increses the power density of the cell with a discharge efficiency of 29 %

Cu2+ + 2 OH- gives Cu (OH)2 * 2 H2O

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