Please show me how to solve this ALEKS problem. A ALEKS. Dalton McCom. x v C Che

Question

Please show me how to solve this ALEKS problem.

A ALEKS. Dalton McCom. x v C Chegg Study I Guided S Secure https://www-awhaleks.com alekscgi/xil.exe/ 10 ulgNskr7 8P3Hlijk6J-TZh4JYCM26JUOtYisau7L4eSupJ4HdZeBk59K4Yg79IOAHmofacgecqhf1 PPWP5a1a7TRbGs3ou ( ENTROPY AND FREE ENERGY - Dalton Calculating dG from dH and ds A chemical engineer is studying the two reactions shown in the table below. In each case, he fils a reaction vessel with some mixture or the reactants and products at a constant temperature of 116.0 eC and constant total pressure. Then, he measures the reaction enthalpy H and reaction entropy S of the first reaction, and the reaction enthalpy and reaction free energy G of the second reaction. The results of his measurements are shown in the table. alo Complete the table. That is, calculate G for the first reaction and AS for the second. (Round your answer to zero decimal places.) Then, decide whether under the conditions the engineer has set up, the reaction is spontancous, the reverse reaction is spontancous, or neither forward nor reverse reaction is spontaneous because the system is at equilibrium S 195. 2NoCI s) - 2NOG) +23) Which is spontaneous? this reaction the reverse reaction O neither AH--12. k G-23. k Sa(s) + 2CO2(g) SnO2(s) + 2coG) Which is spontaneous? this reaction the reverse reaction O neither Explanation Check 46:38

Explanation / Answer

1.

deltaG = deltaH - TdeltaS = 76 - (116.0+273.15)(0.195) = + 0.116 kJ

Since deltaG is positive,

the reverse reaction is spontaneous.

2.

deltaG = deltaH - TdeltaS

23. = - 12 - (116.0 + 273.15)deltaS

(116.0 + 273.15)deltaS = - 12 - 23

deltaS = - 35 / 389.15 = - 0.0899 kJ/K = - 89.9 J/K

Since deltaG is positive, the reverse reaction is spontaneous.

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