com/myct/itemView?assignmentProblemID-97505273 K11 of 19> odic Table Part A of t

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com/myct/itemView?assignmentProblemID-97505273 K11 of 19> odic Table Part A of the re to the 1)Like en gas to alanced Determine the balanced chemical equation for this reaction CsHs(9)+02(9)C02(9)+HO(g) Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C His. two moles of O2, three moles of CO2, and four moles of H20. e 20(9) View Available Hint(s) 2,25,16,18 Correct It is important to balance a chemical equation before using it for calculations Checking that equations are balanced will help you avoid many errors in chemistry problems 1of1 Balanced chemical equation 2CsHis(s) +2502(9)+16CO2(9) + 18 H20(s) Part B 0.290 mol of octane is allowed to react with 0 630 mol of oxygen Which is the limiting reactant? ·View Available Hint(s) octane " oxygon Previous Answers

Explanation / Answer

Balanced equation:
2 C8H18 + 25 O2 ====> 16 CO2 + 18 H2O
Reaction type: combustion

0.29 Moles of Octane needs 3.624 Moles of Oxygen

But 0.69 Moles of oxygen needs 0.0504 Moles of Carbon

Hence Oxygen is limiting reagent.

Moles of water produced =  0.4536 Moles

Mass of H2O Produced = 0.4536 x 18 = 8.1648 gm

Mass of octane present before reaction = 0.29 x 114.22 =  33.12 gm

Mass of octane used = 0.0504 x 114.22 =  5.757 gm

Mass of octane left over after reaction = 33.12 - 5.757 = 27.363 gm

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