Sugar contained in Coca-Cola produces normal freezing point of water in the can.

Question

Sugar contained in Coca-Cola produces normal freezing point of water in the can. There are 39 g of fructose (MM = 180.16g/n) in one 355 mL can. How many degrees Celsius does the sugar reduce the freezing point of water in the can?
KfH2O = 1.86 degrees Celsius x kg/n Density of coke = 1.11g Sugar contained in Coca-Cola produces normal freezing point of water in the can. There are 39 g of fructose (MM = 180.16g/n) in one 355 mL can. How many degrees Celsius does the sugar reduce the freezing point of water in the can?
KfH2O = 1.86 degrees Celsius x kg/n Density of coke = 1.11g
KfH2O = 1.86 degrees Celsius x kg/n Density of coke = 1.11g

Explanation / Answer

Weight of solvent= volume* density= 355 mL * 1.11 g/ mL

= 394.05 g

=0.394 kg

We know that T f = Kf x m
Where
T f = depression in freezing point
= freezing point of pure solvent – freezing point of solution
= 0 -Tf

= - Tf
K f = depression in freezing constant= 1.86 oC/ m
m = molality of the solution
= ( mass / Molar mass ) / weight of the solvent in Kg

= ( 39 g/180.16(g/ mol))/0.394 kg

= 0.549 m

Plug the values we get Tf= -1.02 oC

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.