Pad 5:58 23%D+ D CengageBrain . M × owLv2 | Online te × \' G A Student Determ ×
ID: 1029220 • Letter: P
Question
Pad 5:58 23%D+ D CengageBrain . M × owLv2 | Online te × ' G A Student Determ × ogle × C cvg.cengagenow.com/ilm/takeAssignment/takeCovalen. CH 17 FREE ENERGY Question 5 Use the Refereaces to access important values if peeded for this question Question 6 The equilibrium constant, K for the following reaction is 10.5 at 350 K Question Question 8 Question 9 Question 71 pt 1 pt 1 pt 10 1pt 1 pt 1 pt 1 pt If 11° for this reaction is-18.8 k, what is the value of Kp at 430 K? Question 11 Question 12 Question 13 Question 14 Question 15 Submit Answer Try Another Version 5 item attempts remaining pf 1 pt 1 pt 1 pt 1pt Question 16 Question 17 Question 18 Question 19 Question 20 17/20 items Due Mar 18 at 11:55 PM Previous Finish Assignment Email Instructor Save and Exit Cengage Learning | Cengage Technical SupportExplanation / Answer
Kp = 10.5 at T1 = 350 K
Kp = ? at T2 = 430 K
dH = -18800 J
R = gas constant
Using,
ln(k2/k1) = dH/R[1/T1 - 1/T2]
ln(k2/10.5) = -18800/8.314[1/350 - 1/430]
k2 = 3.16
So,
Kp at 430 K = 3.16
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.