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owLV2 l Online teaching and G Solved: A sample of nitrogen G hydrogen gas molar

ID: 1029121 • Letter: O

Question

owLV2 l Online teaching and G Solved: A sample of nitrogen G hydrogen gas molar mass-c × x nmen ity.do locator-assignment-take&takeAssignmentSessionLocator; assignment-take Use the References to access important values if needed for this question. A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 713 mm Hg. Express this pressure in atmospheres, kilopascals, torrs, pounds per square inch, and pascals. Hint: l atm-101.3 kPa = 760 torr -760min Hg -14.69 psi = 1.013-105 Pa mm Hg atm kPa torrpsiPa 713 Submit Answer Retry Entire Group 9 more group attempts remaining 18 F7 F10

Explanation / Answer

1 atm = 760 mmHg

So 713 mm Hg = 713 / 760 = 0.93816 atm

1 atm = 101.3kPa

So 0.93816 atm = 0.93816 x 101.3 = 95.035 kPa

1 atm = 760 torr

So 0.93816 atm = 0.93816 x 760 = 713 torr

1 atm = 14.69 psi

So 0.93816 atm = 0.93816 x 14.69 = 13.78 psi

1 atm = 1.013 x 105 Pa

So 0.93816 atm = 0.98316 x 1.013 x 105 = 9.5 x 104 Pa