drogen bonds? A) amide B) alcohol C) alkene -hydro cr ban D) carboxylic acid E)
ID: 102873 • Letter: D
Question
drogen bonds? A) amide B) alcohol C) alkene -hydro cr ban D) carboxylic acid E) all of these can hydrogen bond amide al cohol Professor Snape adds 0.1611 g of an unknown gas to a 125-mL flask. If Snape finds the pressure to be 736 torr at 20.0°C, is the gas likely to be methane, CH4, nitrogen, N2, oxygen, 02, neon, Ne, or argon, Ar? A) CH4 B) Ar C) Ne D)N2 E) 02 8 Which of these factors gives rise to the primary structure of a protein? 18. A) DNA sequence B) dispersion forces within the protein's interior. C) hydrogen bonding of backbone amides D) formation of helical and sheet regions E) interactions between the amino acid side chains Polyamides such as kevlar can be prepared by the reaction of 19. A) a diamine with a carboxylic acid. B) a diamine with a dicarboxylic acid. C) an amine with a dicarboxylic acid. D) a diol with a dicarboxylic acid. E) an alcohol with a dicarboxylic acid.Explanation / Answer
16) A0 Amide: In amide -CO-NH2, we have hydrogen atom and an electronegative -O atom, which can form H-bonding.
Hence, this option is not correct.
B) Alcohol: Alcohol also contains hydrogen and oxygen atom which form a hydrogen bond. Hence, this option is
not correct.
C) Alkene: Alkene is hydrocarbon, which basically contains Hydrogens and Carbons, but it does not contain any
electronegative atoms like O, N, F etc. Therefore, this molecule does not form hydrogen bonding.
Hence, this option is correct.
D) Carboxylic acid: Since it contains both H and O atom, it can form H-bonding. This option is not correct.
E) since option C is correct. This option is not valid.
Hence, the correct answer is: C (alkene)
17) Mass of unknow gas = 0.1611 g
Volume V = 125mL = 0.125 L
Pressure = 736 torr = 0.968421 atm
T = 20 oC = 273 + 20 = 293 K
R = 0.08205 L atm / mol·K
Ideal gas equation:
PV = nRT
n = PV/RT
= (0.968421 atm x 0.125 L) / (0.08205 L atm / mol·K x 293 K)
= 0.005 mol
mass/mol.wt = 0.005 mol
mol. wt = mass/0.005 mol
= 0.1611 g/ 0.005
= 32 g/mol
Therefore, the unknown gas molecular wt is 32 g/mol. Since, O2 mol.wt = 32 g/mol, the unknown gas is O2.
Hence, the answer is: E(O2)
18) The primary structure of a protein is a polypeptide which is encoded in DNA.
Hence the answer is: A) DNA Sequence.
19) Answer: B (a diamine with a dicarboxylic acid)
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