15-ANION ANALYSIS EXERCISES 1. The following results were obtained by a student

Question

15-ANION ANALYSIS EXERCISES 1. The following results were obtained by a student with "superperfect" lab techniques. Give the anions that are present, absent, or indefinite (not en- ough or no information is given). No yellow dye is present in the original unknown. All nine anions must appear in one of the answer blanks below. The pH or the anion soln. was adjusted to 12.1. After complete precipitation using barium nitrate, yellow ppt(1) and soln(1) were obtained. The addition of dilute nitrie acid to yellow ppt (1) caused the formation of only clear yel- low soln (2). After the pH was adjusted to 1.5 in soln(1), it was heated for 10 min. After silver nitrate was added to this soln(1) to obtain complete pre- cipitation, yellow ppt(2) and soln(3) were obtained. After 0.3 M ammonium hydroxide was added to yellow ppt(2), soln(4) and yellow ppt(3) were ob- After the silver acetate treatment to remove any interferences, the careful addition of cone. sulfuric acid and ferrous ammonium sulfate to the original unknown soln caused the formation of a brown ring. The addition of ferrie nitrate to another portion of the original solution after it had been acidified with nitric acid, gave only a clear pale yellow solution. Anions Present Anions Absent Anions Indefinite 2. Given the following ways anions A, B-, C- and D- may react, print a schematic for the separation of these ions in an aqueous solution contain- ing all of these ions. a) SrA, SrB SrC and SrD, are insoluble in water b) SrA, SrB, SrC, and SrD, are all soluble in cone. H,SO c) Only SrA, is soluble in 6 M HNO d) Only SrA SrB and SrC are soluble in 12 M NH,OH e) Only SrA, and SrB, are soluble in 0.1 M NH,OH 3. What is the oxidation number of Br in NaBrOg? 4. What is the color of each of the following compounds? a) NaSCN b) K,CrO 5. Write the formula for each of the following compounds. a) sulfuric acid b) silver chromate

Explanation / Answer

5. The formula for sulfuric acid is H2SO4.

The formula for silver chromate is Ag2CrO4

4. NaSCN is colorless.

The color of K2CrO4 is yellow.

3. 1+ x + 3(-2)=0

So x=5.

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