A) K-[O21-1 C k.IKCioP102P D) K-1O2 16) De e the value of Ke for the following r
ID: 1028174 • Letter: A
Question
A) K-[O21-1 C k.IKCioP102P D) K-1O2 16) De e the value of Ke for the following reaction if the equilibrium concentrations are as follows: [N 1.5 M, [H2leq = 1.1 M, [NH3leq 0.47 M. 2lesq N2 (g) + 3 H2(g) NH3(g) A) 3.5 B) 0.28 C) 0.78 D) 0.11 E) 9.1 17) In a reaction mixture containing only reactants, what is the value of Q? A) 0 D) It cannot be determined without concentration 18) Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium concentration of NO2(8). N204(g) 2 NO2(g) Ke*0.21 N204leg 0.039 M C) 9.0 x 10-2 M D) 1.22 M A) 8.2 x 10-3 M B) 11 M 19) Consider the following reaction at equilibrium. What effect will adding more H2S have on the system? 2 H2S(g) +3 O2(g) 2 H20(g)+2 SO2(g) il be observed.Explanation / Answer
16) N2(g) + 3 H2(g) = 2 NH3(g)
Kc = [ NH3]^2 / [N2] [ H2]^3
Kc = ( 0.47 ) ^2 / ( 1.5 ) ( 1.1)^3
Kc = 0.2209 / (1.5) ( 1.331)
Kc = 0.2209 / 1.9965
Kc = 0.11
the answer is D
17) the answer is A) 0
18) N2O4(g) 2 NO2(g)
expression for Kc:
Kc = products / reactants
Kc = [ NO2]^2 / [ N2O4]
given Kc = 0.21
[ N2O4] = 0.039
substituting the values
0.21 = [ NO2]^2 / 0.039
[ NO2]^2 = 0.21 * 0.039 = 8.19*10^-3
sqrt( [ NO2] ^2) = sqrt( 8.19*10^-3)
[ NO2] = 9.0*10^-2 M
the answer is C
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