uestion Completion Status: QUESTION 3 What is the mass (in grams) of 8.45 x 1023

Question

uestion Completion Status: QUESTION 3 What is the mass (in grams) of 8.45 x 1023 molecules of dextrose: CGH1206 (Mw. 180.16 g/mol)? QUESTION 4 How many moles is equivalent to 9.34 x 1022 molecules of nitrogen dioxide: NO2 (Mw. 46.01 g/mol)? QUESTION5 How many moles of Pb(SO4)2 are equivalent to 138.1 g of Pb(SO4)2 (Mw. 399.34 g/mol)? QUESTION 6 How many formula units of NaNO3 are in 9.82 moles of NaNO3 (Mw. 85.00 g/mol)? QUESTION 7 Click Save and Submit to save and submit. Click Save All Anwers to save all answers

Explanation / Answer

3. to covert molecules into moles divide it by avagadro number

moles= 8.45*1023/6.02*1023 =1.4

moles= mass/M.W

mass= moles*M.W

= 1.4*180.16

=252.88g

4. moles =molecules/6.02*1023

=9.34*1022/6.02*1023

=0.155

5. moles =mass/M.W

=138.1/399.34

=0.34

6. formula units = moles* 6.02*1023

= 9.82*6.02*1023

= 5.91 * 1024

5

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