beyond 40°C because the pressure increase may pUp remove some of the water in th
ID: 1027590 • Letter: B
Question
beyond 40°C because the pressure increase may pUp remove some of the water in the bath, do it carefully so as not to disturb the flask flask. Remove the flask from the water bath and take the stopper off the flask. Dispose of the ethanol as directed 15. After you have recorded the fifth set of readings, open the valve to release the pressure in the Stop data collection. Tap Table to see the temperature and pressure measurements. Record the pressure readings, as Pooal, and the temperature readings in your data table 16. DATA TABLE Initial Trial 1Trial 2 Trial 3 Trial 4 Trial 5 Protal (kPa) Par (kPa) 100.8 1012b lo.s02.08 l03.2 lo4.3 5 .33 3.3711.36 Temperature () 123.8 | 24.3 | 25.0 | 20.1 | 275 | 28.7 Pap (kPa)Explanation / Answer
Dear Friend your answers are
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3) Yes, the plot followed expected trend of the effect of temperature on vapor pressure as we can seen the straight line from the scattered graph. This trend is in accordance with Gay-Lussac's law, states that if temperature of a gas is increases then pressure is also increases at constant volume.
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4) From the graph we got straight line equation (like y = mx + c) y = -43909x + 148.55; here "m" is the slope and also "A" in ln(vapor pressure) = -A/T + B equation and equals to Hvap= 43909 J/mol = 43.91 kJ/mol.
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5) Accepted value = 42.32 kJ/mol and experimentally determined value = 43.91 kJ/mol. The difference between Accepted value and experimentally determined value = 43.91 - 42.32 = 1.59 kJ/mol only. This difference arise due to either instrumental error (non-calibrated thermometer and pressure guage) or human mistake (parallax error etc) if it is a non-digital instrument.
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