1. mass of covered crucible 2. mass of covered crucible + hydrate 3. mass of cov

Question

1. mass of covered crucible 2. mass of covered crucible + hydrate 3. mass of covered crucible + residue, after heating CALCULATIONS FROM DATA 4. mass of sample (hydrate): (line 2-line1) 22:535- 21-3-g 2-012 4 16 5. mass of residue (anhydrous salt):(line 3- line1) 252 6. mass of water lost: (line 4 - line 5) OBSERVATION Water added to the anhydrous copper (II) sulfate:--tquandhwe PROCESSING THE DATA: In the space provided set up each calculation. Calculate molecular masses to two decimals. Round answers to the correct number of significant figures before putting your answer in the space provided mwaterlB) 1 (mol) )-- X MMwaterle) 1. Calculate number of mol water: nwater (mol MMwater B) Where: mwater is mass of water lost, g MMwater is molar mass of water, g/mol mol nwater

Explanation / Answer

1) moles of water = 0.76/18= 0.042222 moles

2) mCuSO4= 1.252. molar mass of anhydrous CuSO4= 159.609

moles of CuSO4 = 1.252/159.609= 0.007844

3) moles ratio = moles of water/moles of CuSO4= 0.0422/0.00784= 5.38 == 5

4)  CuSO4.5H2O

5) % water in hydrate= 0.76/2.012*100= 37.77%

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.