C. Silver Acetate/Silver Nitrate mL standard KCI taken Titration volumes Sample

Question

C. Silver Acetate/Silver Nitrate mL standard KCI taken Titration volumes Sample 2 Sample 3 (if needed) Samplel Initial volume AgAc Volume AgAc used Molarity of Ag ion Mean molarity of Ag ion Molar Solubility AgAc in AgNO, .orM losl mL standard KCI taken Titration volumes Sample Initial volume AgAeSORo Final volume AgAc,/./yal Volume AgAc usede.ol Sample 2 Sample 3 (if needed) Molarity of Ag ion Mean molarity of Ag' ion Molar Solubility of AgAc in NaAc Based on Parts A, and B calculate a mean value and the standard deviation for Ksp for silver acetate. 122

Explanation / Answer

The overall reaction is :

KCl+ AgAc -----------> KAc + AgCl

Molarity of KCl = 0.05 moles/litre

Volume of KCl - 10.00 ml = 10.00 X 10-3 L

moles of KCl = 0.05 moles/L * 10.00 X 10-3 L = 0.50 X 10-3 moles

from the above reaction:

moles KCl = moles AgAC = moles Ag+ = 0.50 X 10-3 moles

molarity Ag+ (trial 1)= moles Ag+/Volume of Ag+ = 0.50 X 10-3 moles/ 18.01 X 10-3 L = 2.78 X 10-3 M

molarity Ag+ (trial 2)= moles Ag+/Volume of Ag+ = 0.50 X 10-3 moles/ 18.31 X 10-3 L = 2.73 X 10-3 M

Mean molarity Ag+ = (2.78 X 10-3 M + 2.73 X 10-3 M)/2 = 2.76 X 10-3 M

Molarity of Ac- = molarity of Ag+ =2.76 X 10-3 M

Molar solubility of AgAC = [Ag+][AC-] = (2.76 X 10-3)X(2.76 X 10-3)= 7.62 X 10-6

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