Sapling Learning macmillan learning Map Consider this reaction data: If you were

Question

Sapling Learning macmillan learning Map Consider this reaction data: If you were going to graphically determine the activation energy of this reaction, what points would you plot? A products T (K) k (s) 275 0.385 725 0.657 Number Number point 1 To avoid rounding l errors, use at least three significant figures in all values Number Number point 2 Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number What is the activation energy of this reaction? Number J/ mol O check Answer e Next O Previous Give Up & View Solution Exit Hint

Explanation / Answer

Arhenius equation will be used to calculate the activation energy

The equation is lnK=lnKo-Ea/RT, where K is the rate constant corresponding to the temperature in K. Ea is activation energy and R= gas constant= 8.314 J/mole.K and T is temperature in K

at two different temperatures T1 and T2, where the rate constants are K1 and K2

the equation becomes ln (K2/K1)= (Ea/R)*(1/T1-1/T2)

or lnK2-lnK1= Ea/R*(1/T1-1/T2)

slope is -Ea/R = ln(K2/K1)/ (1/T2-1/T1)= difference in y axis/ different in x axis

hence x1= 1/T1= 1/275= 0.0036/K and K1=0.385/sec, lnK1(y1)= ln(0.385) = -0.9545, x2= 1/T2= 1/725=0.001379/K

K2= 0.657/sec, lnK2(y2)= -0.42, rise = difference in y axis = -0.42-0.9545= 0.5345 and run= difference in x axis = 0.0036-0.001379=0.002257,

slope = -Ea/R= -rise/run=-0.5345/0.002257=-236

Ea=236*8.314 j/moles =1969 joules/mole

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