A) 92, 146, 87 B) 146, 92,97 C) 92, 146, 92 D) 92,92,87 E)146, 92,92 11) Resonan
ID: 102715 • Letter: A
Question
A) 92, 146, 87 B) 146, 92,97 C) 92, 146, 92 D) 92,92,87 E)146, 92,92 11) Resonance structures differ by A) number of atoms only B) number of electrons only C) number and placement of electrons D) placement of electrons only E) placement of atoms only 12) What species has the electron configuration [Ar]3d2? A) V3+ B) K+ C) Cr+ D) Mn2+ E) Fe3+ 13) Which of the following would have to lose three electrons in order to achieve a noble gas electron configuration? Si Mg Al CI P A) Si, P B) A C)Mg, Al, P D) CI E)P non bonding and 14) The Lewis structure of PF3 shows that the central phosphorus atom has bonding electron pair(s). A) 3,3 B) 1,2C)2,2 D) 3,1E) 1,3 A) 3- B) 2 15) Aluminum forms an ion with a charge ofExplanation / Answer
11) D. Answer is D, since it is just movement of pi electrons across the system making the system delocalized.
12) A. Answer is A. Since electronic configuration of V is [Ar] 3d3 4s2.
So loss of 3 electrons give the desired configuration of V3+
13. B. Since Al has 13 electrons so they loose 3 electrons to become 10 that is number of electrons in Ne.
14. E. Since P has 15 electrons so has 5 outermost electrons. So uses 3 electrons to form 3 bonds and 2 electrons form non bonding pair of electrons.
15. D. Since it looses 3 electrons to get noble configuration of Ne - a noble gas.
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