STOICHIOMETRY Identifying the limiting reactant in a drawing of a mixture The dr

Question

STOICHIOMETRY Identifying the limiting reactant in a drawing of a mixture The drawing below shows a mixture of molecules: key | 0 O carbon hydrogen O nitrogen sulfur O oxygen chlorine Suppose the following chemical reaction can take place in this mixture: 2C2H2(g)+SO2(g)_+4CO2(9) + 2H2Og) of which reactant are there the most initial moles? Enter its chemical formula: of which reactant are there the least initial moles? Enter its chemical formula: 0 Which reactant is the limiting reactant? Enter its chemical formula 0o Explanation Check MacBook Pro esc Yeah And 2 4 5 6 8

Explanation / Answer

Highest number of moles of Reactant = O2 (10 moles )

Lowest number of moles of Reactant = C2H2 ( 5 moles )

Here the limiting Reactant is O2,

Since from the reaction 2 moles of C2H2 needs 5 moles of O2

Hence, 5 moles of C2H2 needs ? moles of O2

= (5×5)/2

= 12.5 moles of O2

But we have only 10 moles of O2

Hence O2 is limiting Reactant.

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