For questions 26-27, consider the 2 containers of the same unknown gas shown bel

Question

For questions 26-27, consider the 2 containers of the same unknown gas shown below. Container A: T = 27°C Container B: T =-123°C 26)lf both containers have the same number of moles of gas and the container on the left has a volume that is twice as large as the container on the right. Which of the following statements is correct? I. The pressure in the two containers is the same. II. The gas particles in container A are hitting the sides of the container harder because their temperature is higher. III. The frequency with which individual gas particles hit the sides of the container is higher in container B a. Only I is correct b. Only II is correct c. Only I and Il are correct d. Only II and III are correct e. I, II and III are correct 27)If the rate of effusion of the gas in container A is 515 m/s, what would its rate of effusion be at 327°C? a. 6.24 km/s b. 1.79 km/s c. 1030 m/s d. 728 m/s e. 537 m/s

Explanation / Answer

(26)

Data given:

Va = 2*Vb

Ta = 270C = 300 K

Tb = -1230C = 150 K

Since the number of moles of gas are same in both the containers, so using the relation:

PaVa/Ta = PbVb/Tb

Putting values:

Pa*2Vb/300Ta = PbVb/150Tb

Solving we get:

Pa = Pb

So the pressure in both containers is same.

So, Only I is correct.

(27)

The effusion rate directly depends on the average velocity of gas, which in turn is directly proportional to square root of temperature.

Since the temperature increases from 300 K to 600K, so it doubles.

So, the average velocity will increase by a factor of 20.5 = 1.414

So, final effusion rate = 515*1.414 = 728 m/s

Hope this helps !

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