In one experiment 20 mL of 5.43x10^-3 M FE(NO3)3 and 10 mL 6 M HNO3 was placed i

Question

In one experiment 20 mL of 5.43x10^-3 M FE(NO3)3 and 10 mL 6 M HNO3 was placed in a 100 mL volumetric flask and diluted to the mark with distilled water. What was the concentration of iron(III) nitrate in the final solution? (This is a dilution problem) In one experiment 20 mL of 5.43x10^-3 M FE(NO3)3 and 10 mL 6 M HNO3 was placed in a 100 mL volumetric flask and diluted to the mark with distilled water. What was the concentration of iron(III) nitrate in the final solution? (This is a dilution problem)

Explanation / Answer

final volume of the solution = 100ml

Fe(NO3)3 = 20 ml of 5.43x10^-3M

M1= 5.43x10^-3M

V1= 20ml                       V2= 100 ml

M1V1 = M2V2

5.43x10^-3 x 20 = M2 x100

M2= 108.6 x10^-5

M2 = 1.086 x10^-3M

final concentration of Fe(NO3)3 = 1.09 x10^-3M

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