32. The reaction of HCI with NaOH is represented by the equation HCI(aq) + NaOH(
ID: 1026530 • Letter: 3
Question
32. The reaction of HCI with NaOH is represented by the equation HCI(aq) + NaOH(aq) NaCl(aq) + H200 What volume of 0.668 M HCI is required to titrate 2 a, 9.79 mL b.1.49 mL c. 21.9 mL d, 27.2 mL 7.2 ml of 0539 MNaOtH? e, 33.7 mL 33. 2Al(s) + 6HCI(aq) 2AlCly(aq) + 3H2(g) According to the equation above, how many grams of aluminum are hydrochloric acid? needed to completely react with 2.19 mol of a. 177 g b. 26.6 g c. 19.7 d.2.19g e.59.1 g 34. Consider the fermentation reaction of glucose A 1.00-mol sample of CsH1 Os was placed in a vat with 100 g of yeast If 37.0 g of CallsOH was obtained, what was the percent yield of C2HsOH? a, 40.2 % b, 20.1 % c. 37.0% d. 100% e. none of these 35. Nitric oxide, NO, is made from the oxidation of NH3 as follows: 4NH3 + SO2 4N0 + 6H20 If 9.6-g of NH3 gives 12.0 g of NO, what is the percent yield of NO? a, 93 % b, 44 % c. Il%_ d. 71% e, 28 % 36. What is the pH of 23x 10-3 M HCI(aq)? a.-1.01 b. 2.54 c. 3.50 d. 1.01 e.5.65 37, What mass f iron can be produced fom te eactin of 175 kg Fe0j with 385 kg Co? Fe2O3(s) + 3 CO(g) 2 Fe(s) + 3 CO2(g) a. 2.19 kg b. 30.6 kg c. 61.2 kg d. 122 kg e.512 kg E Aouad Spring 2018 CHM 103Explanation / Answer
HCl(aq) + NaOH(aq) -------------> NaCl(aq) + H2O(l)
1 moles 1 moles
HCl NaOH
M1 = 0.668M M2 = 0.539M
V1 = V2 = 27.2ml
n1 =1 n2 =1
M1V1/n1 = M2V2/n2
V1 = M2V2n1/M1n2
= 0.539*27.2*1/0.668*1
= 21.9ml
C. 21.9ml
33. 2Al + 6HCl -------------> 2AlCl3(aq) + 3H2(g)
6 mmoles of HCl react with 2 moles of Al
2.19 moles of HCl react with = 2*2.19/6 = 0.73 moles of Al
mass of Al = no of moles * gram atomic mass
= 0.73*27 = 19.7g
C. 19.7g
34. C6H12O6 -------> 2C2H5OH + 2Co2
1 mole of C6H12O6 to gives 2 moles of C2H5OH
180g of C6H12O6 to gives 2*46g of c2H5OH
= 92g of C2H5OH
The theoretical yiled of C2h5OH = 92g
percent yiled = actual yiled *100/theoretical yiled
= 37*100/92 = 40.2%
a. 40.2%
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