So4 Unknown no. 1. Mass of fired crucible and lid (g) 2. Mass of fired crucible,

Question

So4 Unknown no. 1. Mass of fired crucible and lid (g) 2. Mass of fired crucible, lid, and hydrated salt (g) 3. Instructor's approval of flame and apparatus 4. Mass of crucible, lid, and anhydrous salt Trial 1 Trial 2 Trial 3 31, 597T 42.5400 32,2S27 1st mass measurement (g) 2nd mass measurement (g) 3rd mass measurement (g) 42.1818 32,6 9r2 41,17832.089 5. Final mass of crucible, lid, and anhydrous salt (g) Calculations 2.515 7 274 2:sis 2.nes 1. Mass of hydrated salt (g) 2. Mass of anhydrous salt (g) 3. Mass of water lost (g) SS28 * rner 4. Percent by mass of volatile water in hydrated salt (%) s.ye Dato Analysis, B Average percent H2O in hydrated salt (%H2O) mols anhydrous 5. Data Analysis, mols Hr e Data Analysis, D 7. *Show calculations on next page. 8. Formla Hydrate Experiment 5 89

Explanation / Answer

Number of anhydroud moles :-(1.3906/136 + 1.4339/136)/2= 0.0135

Number of H2O moles:-(1.1251/18 + 1,1428/18)/2 = 0.06295

This implies that for 0.0135 moles of anhydrous CaSO4, 0.06295 moles of H2O are present.

Hence, for 1 mole of CaSO4, number of moles of water present :- (1/0.0135)*0.06295= 6.08= aprroximately 6 moles of water.

Hence, formula of hydrite = CaSO4 .6H2O

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