If I have a four component mixture of 5mL of benzoic acid, ethyl 4-aminobenzoate
ID: 1026257 • Letter: I
Question
If I have a four component mixture of 5mL of benzoic acid, ethyl 4-aminobenzoate, 1-chlorobutane, and toluene. It is determined that 1.0 mL of 1-chlorobutane and 1.0 mL of toluene was part of the four component mixture and 100% yield of ethyl 4-aminobenzoate was 100 mg. What is the percent yield of benzoic acid when I have an experimental weight of 0.115?
Benzoic Acid Ethyl 4-amínobenzoate 1-Chlorobutane Toluene Saturated N HCT4ic Ethyl 4-aminobenzoate 1-Chlorobutane Toluene Organic HCI (6M) Extraction Aqueous 100 mg NaeCle Concentrated HCI 1-Chlorobutane Toluene Organic Dry MgSO4 Boil off Ether Distillation Q (impure) Aqueous Sublimation mPoHe CH3CH2C2CH2C CH3 INE Benzoic acid (pure) (pure) (pure) Report weight Report weightr Report weight b.p G.C. m.p. p. G.C Report weight b.p.Explanation / Answer
1ml is 1-chlorobutane and 1ml is toluene
volume of ethyl 4-aminobenzoate = m/density
= 0.1g/1.17
=0.085ml
total volume of these three components= 1+1+0.085= 1.085ml
left out volume is obviously benzoic acid = 5-2.085= 2.915ml
theoritical yield= mass= density *volume= 1.27 * 2,915= 3.70gm
experimental weight= 0.115g
so percent yield = (experimental yield/theoritical yield ) *100
= (0.115/3.7)* 100
= 3.11%
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