4 Jumpt ning Gradebook re 3/10/2018 11:59 PM 84.2/100 3/10/2018 09:13 PM Pnni |

Question

4 Jumpt ning Gradebook re 3/10/2018 11:59 PM 84.2/100 3/10/2018 09:13 PM Pnni | Cakuukx bnd Period. Table Question 37 of 40 Mapdes Sapling Learning The flask shown here contains 10.0 mL of HCI and a fevw of phenoiphthalein indicator. The buret contains 0 200 M NaOH What volume of NaOH is needed to Number 50 ml. NaOH What was the iniial concentration of HC? Click to begin 10 M HCI There is a hint avalabie! View the dvider bar ain to hide the hint Previous&Give; Up & View Sclution Check AnswerO Next Ext about us : careers privacy polcy terms ofuse I contact us I heo cBookAi 8 3 5

Explanation / Answer

Ans. Given, molarity of standard NaOH = 0.200 M

Volume of NaOH consumed to reach endpoint = 50.0 mL. (Note: This value is to be determined experimentally/ virtual titration. If the volume of NaOH consumed is not correctly recorder, the calculate value of [HCl] would not be correct, too).

Volume of HCl being titrated = 10.0 mL

# The acid is monoprotic and the base is monobasic. So, at the titration endpoint-

            M1V1 (NaOH) = M2V2 (HCl)

            Or, 0.200 M x 50.0 mL = M2 x 10.0 mL

            Or, M2 = (0.200 M x 50.0 mL) / 10.0 mL

            Hence, M2 = 1.00 M

Therefore, [HCl], M2 = 1.00 M

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.