..ooo Verizon 12:01 PM 65% bb.wpunj.edu (16) [10pts; Show work for credit Mind t
ID: 1025773 • Letter: #
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..ooo Verizon 12:01 PM 65% bb.wpunj.edu (16) [10pts; Show work for credit Mind the units] The density of a0.750M solution of HSo, n water is 1.046 g/mL at 20°C. Suggestion: Make an assumption on how much solution you have. (a) [2pts] Calculate the molar mass of solute? b) [4pts] Caloulate the mass percent of the solution? (c) [4pts] Calculate the molality of the solution? (17) [10pts; Show work for credit, Mind the units] An aqueous solution has an osmotic pressure of 12.5 mmtig at 300K. The solution was made by dissolving 20.0 mg (milligram) of solute in a small amount of solvent and then bringing the final volume of the solution to 5.00mL (a) [lpt] What is the solvent of the solution? ) [3pts] Calculate the molarity of the solution? ()[3pts] Calcuiate the number of moles of solute in the solution? (d) [3pts] Caloulate the molar mass of the solute? (18) [20pts; Show work for credit; Mind the units] The concentration-time data for 2N0 s) 2NO(g) +01g) at 300 are tabulated and plotted as folows In INO 8.00 × 103 638 × 10-3 599 × 10-3 485 × 10-3 429 × 10-3 3 × 10-3 293 x 10 253 x 10 152 200 233 41 500 x00 10 (a) [pts] Write an expression for the reaction rate specific for the reaction given above based on concentration change. Be as specofic as possible. (b) [2pts) Based on the plots given above, what is the overall reaction order? Justify your answer ()[2pts] Write the rabe law for the reaction based on your answer in (b). () [apts] Which part/berm of your rate law expression in (c) is temperature-dependent? (e) [4pts] Calculate the rate constant at 300 n [4pts] Galculate the concentration of NO at t 20.0min? (s) [4pts] Calculate ta when [NO,, is 6.00x10 MExplanation / Answer
ans 16
a)
molar mass = mass of 2(H) + S + 4(O) = 2+ 32 + 4(16) = 98 g/mol
ans 2
1) Assume 1.0000 L of the solution is present. Determine the mass of the solution:
(1.046 g/mL) (1000.0 mL) = 1046 g
b) Determine the mass percent of each component:
Mass of H2SO4 ---> 98 g * 0.750 M * 1 L = 73.55 g
H2SO4 ---> 73.55 g / 1046 g *100 = 7.03 %
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