Vi. Preparation of Eugenol (Synthetic Clove Oil) Last week, we attempted the syn

Question

Vi. Preparation of Eugenol (Synthetic Clove Oil) Last week, we attempted the synthesis of an allyl aryl ether, the precursor for the preparation of synthetic eugenol. Recall that eugenol is the main component of clove oil, a natural product that we steam distilled to purify in Chemistry 231L. The overall reaction scheme from this preparation of eugenol is given below and your raw data from this experiment is copied below. Allyl bromide (2 eq.) K2CO3 (2 eq.) OH CH3CN Guaiacol M.W. 124.14 2-allyl guaiacol M.W. 164.20 d 1.11g/mL d=1.06 g / mL Part A Mass of guaiacol (reactant) measured 1.12 mL 1.019 g Mass of allyl guaiacol (product) recovered 4. (10 pts) Using the corresponding density (from above), calculate the mass of guaiacol that you started with in this transformation from the volume given. Report your answer in the box provided. Show your work. A correct response without any justification (work) will receive partial credit (2 pts). Place your answer here

Explanation / Answer

Density = Mass/ Volume

Or, Mass = Density x Volume

Now,

Volume of guaiacol = 1.12 mL
Density of guaiacol = 1.11 g/mL

So, Mass of guaiacol = 1.11 g/mL x 1.12 mL
                                     = 1.2432 g

Related Questions

Navigate

• Browse (All)
• Browse V
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.