oo C Spire 5:47 PM 4) Dedoce the identity of he fellowing cumpound trom the 1H N

Question

oo C Spire 5:47 PM 4) Dedoce the identity of he fellowing cumpound trom the 1H NMR data givn 43) Deduce the identity of the lollowing opound om the 1HNMR data giwen (ppm) Deducothe identity ofthw…tzgcomporthom the tH NMR data ghen 45) Dedace he identity of the llowing compound from the HNMR data gven 45) Dedace the idensty ol dhe following compound from the H NMR data given 47) Deduxe dhe identity of the lollowing compound tron the NMck daa given 48) Deduthe identity ofthe blewizgcompound bomtheepea al datapren. inget 345 (tripet 2022 (qute) (ppm) Dashboard Calendar To Do Notifications Inbox

Explanation / Answer

42)

formula = C7H12O4

HD = 2

1H NMR

1.3 ppm (triple, 6H) for CH3 next to CH2

4.2 ppm (quartet, 4H) for CH2 next to CH3

3.4 ppm (singlet, 2H) for CH2 between two C=O groups

Possible structure,

CH3CH2O-CO-CH2-CO-OCH2CH3

-

43)

formula = C5H12O

HD = 0

1H NMR

1.0 ppm (triplet, 3H) for CH3 next to CH2

1.2-1.8 ppm (multiplet, 6H) for 3CH2's in between

3.0 ppm (bs, 1H) for -OH proton

3.8 ppm (triplet, 2H) for CH2 between CH2 and oxygen

Possible structure,

CH3-CH2-CH2-CH2-CH2-OH

--

44)

formula = C7H7NO3

HD = 5

1H NMR

3.9 ppm (singlet, 3H) for CH3 next to oxygen

6.9 ppm (doublet, 2H) for phenyl CH protons ortho to -OCH3 carbon

8.1 ppm (doublet, 2H) for phenyl CH protons ortho to -NO2 carbon

Possible structure,

p-nitro-anisole

4-NO2-C6H4-OCH3

--

45)

formula = C8H18O

HD = 0

1H NMR

0.89 ppm (doublet, 6H) for CH3's next to CH

1.87 ppm (multiplet, 1H) for CH between two CH3's and a CH2

3.17 ppm (doublet, 2H) for CH2 between CH and oxygen

Possible structure,

(CH3)2CH-CH2-O-CH2-CH(CH3)2

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