7. How would you prepare 0.100 L of a 0.020 M solution of acetate ion using sodi

Question

7. How would you prepare 0.100 L of a 0.020 M solution of acetate ion using sodium acetate? Using magnesium acetate?

8. The concentration of ampicillin in a stock solution is 5.00 x 103 µg/mL. (Ampicillin fw 349.41 g/mol) Calculate:

a) µg of ampicillin in 0.100 ml of the solution

b) µmol of ampicillin in 0.100 ml of the solution

c) molarity of ampicillin

d) how to prepare 30.0 mL of a working solution with a concentration of 10.0 µg/ml

9. Describe what is needed to prepare 0.200 L of a 100 µM solution. (FW, anhydrous ATP 487.2 g/mol) The ATP powder available in the laboratory is a trihydrate and has 2 moles of sodium ion per mole of ATP Please calculate the preparaton both ways).

Explanation / Answer

7) moles of acetate = concentartion* volume of solution

                               = 0.020 M*0.100 L

                               = 0.002 mol

Molar mass of sodium acetate = 82.0343 g/mol

moles of acetate = moles of sodium acetate

mass of sodium acetate = 0.002mol*82.0343 g/mol

                                     = 0.164 g

So 0.164 g of sodium acetate is mixed in 0.1 L of water to prepare the required solution.

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