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-3 http:// pling ibis/vi C MSN.com Hotmail, Outlook, Miami Dade College, InterA... My Assignment 9/8/2016 11:00 PM CA 74.6/100 9/2/2016 09:47 PM pts Print HCalculator Period Table Question 16 of 21 00 Sapling Learning Values for Water 901 cal of heat is added to 5.00 g ice at 20.0 °C. Specific heat of H20 (s) 2.087 J (g. C) What is the final temperature of the water? 00 Specific heat of H20(N 4.184 J/(g. C) Number 00 Heat of fusion for H2O 333.6 J/g 00 00 67 17 00 00 00 00 Ch Up & Vi D 2011-2016 Sapling Learning, Inc. 78 privacy policy 3- T ome Welcome to Gradebook Map Next E ntact TOSHIBA Service Station: Software Updates There are uninstalled critical software updates! a Assignment Information Available From: 8/29/2016 06:00 PM 9/8/2016 11:00 PM Due Date: Points Possible: 100 Grade Category: Graded pti Policies: CHM 22 You can check your answers. You can view solutions when you complete or give up on any question You have three attempts per question- There is no penalty for incorrect answers. O eTextbook O Help With This Topi Web Help & Videos O Technical Support and Bug Reports 8:10 9/3/2016

Explanation / Answer

heat q = 901 cal = 901 x 4.184 = 3769.784 J

q = mCp(Tf - Ti) + mdHf

with,

Tf = final temperature

Feeding the given values,

3769.784 = 5 x 2.087 x 20 + 5 x 333.6 + 5 x 4.184 x Tf

Tf = 90.49 oC

Is the final temperature

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