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16 IncorretIncorrecd ' incorrect incorrectIncorrectIncorectIncorrect Incorrect General Chemistry 4th Edtion University Science Books presented by Sapling Learning The equilibrium constant at 23°C for the equation is K-4.50 x 103 bar. Calculate the value ofasno, at 239 . In which direction is the reaction spontaneous when PCls. Ch, and PCls are at standard conditions? Number |-35.81 | kJ / mol The spontaneous direction is to the O right O Gn,'; left With the temperature at 239 and the partial pressures of the gases of PPO,0.261 bar, Pcl,-0.726 bar, and Pro,-1.65x10-6 bar PCI calculate the value of Gm. In which direction is the reaction spontaneous under these conditions? Number 1135.81 The spontaneous right direction is to the left 0r.- kJ/ mol O Previous Give Up & View Solution Try Agan Next Exil Explanation tusheip

Explanation / Answer

PCl5 (g) <--> PCl3 (g) + Cl2 (g)

Given Kp = 4.50 x 103 bar

T = 2390C = (239 +273) K = 512k

R = 8.318 J/ Kmole

At equilibrium

-G0rxn = 2.303 RT log Kp

-G0rxn = 2.303 x 8.318 J/ Kmole x 512K log 4.50 x 103

              =2.03 x 8.318 J/ Kmole x 512 K x 3.65

G0rxn =- 35799.39J/mole = - 35.88kJ/mole

P PCl3 = 0.261bar

PCl2 = 0.726 bar

P PCl5 = 1.65 x 10^-6

Kp = [PCl3] [Cl2] / [PCl5]

       = (0.261bar x 0.726 bar) /1.65 x 10^-6

       = 1.15 x 10^5

Now -G0rxn = 2.303 x 8.318 J/ Kmole x 512K log 1.15 x 105

                         =2.03 x 8.318 J/ Kmole x 512 K x 5.06

G0rxn = - 49628.75J/mole = - 49.63kJ/mole

Reaction is spontaneous in right direction.

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