A 19.0-L helium tank is pressurized to 25.0 atm. When connected to this tank, a

Question

A 19.0-L helium tank is pressurized to 25.0 atm. When connected to this tank, a balloon will inflate because the pressure inside the tank is greater than the atmospheric pressure pushing on the outside of the balloon. Assuming the balloon could expand indefinitely and never burst, the pressure would eventually equalize causing the balloon to stop inflating. What would the volume of the balloon be when this happens? Assume atmospheric pressure is 1.00 atm. Also assume ideal behavior and constant temperature.

Explanation / Answer

From ideal gas equation.

initial pressure P1 = 25 atm

initial volume V1 = 19 L

final pressure P2 = 1 atm

final volume V2 =

P1V1 = P2V2

25*19 = 1 x V2

Total volume V2 = 475 L

19 L of helium are present in tank

Volume of ballon = 475-19

= 456 L

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