PLEASE help! Do not understand how to approach problems 1 and 2. Thank you Write

Question

PLEASE help! Do not understand how to approach problems 1 and 2. Thank you

Write out the half reactions, the net chemical reaction and the E degree for the following electrochemical cell: Pb (s) | Pb^2+ (aq), 1.0 M || Ag^+ (aq), 1.0 M| Ag (s) Write out the half reactions, the net chemical reaction and the E for the following electrochemical cell: Fe (s) Fe^2+ (aq), 0.250 M || Cu^2+ (aq), 1.05 M | Cu (s) Describe how you would make 225 mL of a 0.10 M magnesium sulfate solution using a soluble salt.

Explanation / Answer

1. Half reactions:from cell notation it is evident that Pb is Anode and Ag is cathode.

Anode: Pb=Pb2++2e-

Cathode: 2Ag++2e-=2Ag

Net cell reaction is:

Pb+2Ag+=2Ag+Pb2+

E°cell= E°Ag+/Ag -E°Pb2+/Pb

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