What is Delta S degree for the following reaction at 25 degree C? C_2H_4(g) + 3O

Question

What is Delta S degree for the following reaction at 25 degree C? C_2H_4(g) + 3O_2(g) rightarrow 2CO_2(g) + 2H_2O(g) -21 J/K-mol -28 J/K-mol 0 J/K-mol 28 J/K-mol 21 J/K-mol Consider this initial-rate data at a certain temperature for the reaction described by the following equation: C_2H_2Cl(g) rightarrow C_2H_4(g) + HCl(g). Determine the value and units of the rate constant. 5.60 times 10^-30 s^_1 5.60 times 10^-29 S^-1 0.100 mol s^-1 5.60 times 10^-30 Ms^-1 1.12 times 10^-30 Ms^-1 For the reaction A rightarrow products, time and concentration data were collected and plotted as shown here. The reaction order is___. Zeroth order First order Second order Third order For the reaction in question # 13, the rate constant is___, based on the time and concentration data shown above. 0.011 s^-1 4.6 M s^-1 0.100 Ms^-1 0.850 Ms^-1 The oxidation state of each element in Mn(CrO_4)_2 is:__for Manganese, ___for Chromium, and___for Oxygen. +4, +12, -16 +2, +7, -8 +4, +7, -4 +4, +6, -2 Calculate the equilibrium constant for the process N_2O_4(g) doubleheadarrow 2NO_2(g), given the following equilibrium concentrations: [N_2O_4] = 0.0427 M;[NO_2] = 0.0141 M 0.660 0.330 0.00466 0.129

Explanation / Answer

Questions 11 & 12 Values are not visible

Question 13

Answer b) First order

Question 14

First order reaction equation k = 2.303./ t log [Ao/A]

Substitute in the equation K = 2.303 /30 log [0.85/0.611] = 0.011 S-1

hence answer is a ) 0.011 S-1

Question 15

CrO4 exists as a -2 ion meaning the Mn must be +4.

If CrO4 exists as -2 ions, the oxygen will be -2 to give a total of -8 meaning the Cr must be +6 to get an overall charge of -8.

Therefore: Mn = +4, Cr = +6, O = -2

Hence answer is d

Question 16

K = [NO2]2 / [N2O4]

K =   [0.0141]2 / [0.0427] = 0.00466

Hence answer is c

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.