0.0200 mol of argon gas occupies 7.00L. How many moles argon must be added to in
ID: 1020873 • Letter: 0
Question
0.0200 mol of argon gas occupies 7.00L. How many moles argon must be added to increase the volume to 10.00L? A. 0.0086 B. 0.014 C. 0.00029 For: K2CrO4(aq) + SnCl2(aq) + HCl(aq) SnCl4(aq) + CrCl3(g) + KCl(aq) + H2O(l) : the coefficient for K2CrO4 is A. 3 B. 2 C. 1 An example of a strong electrolye is KCl True False Balancing redox equations in acidic medium: to balance the oxygen atoms, you add water molecule(s). True False For the reaction: Zn(s) + SnCl2(aq) ZnCl2(aq) + Sn(s) ; the reducing agent is: A. Chlorine B. tin C. Zinc Thank you
Explanation / Answer
1.
use the avagadros law
V1/n1 = V2/n2
where V1 = intial volume = 7.0 L
n1 = intial volume = 0.02 mol
V2 = final volume = 10.0 L
n2 = we have to calculate
plug in all these values in above equation
7.0 L / 0.02 mol = 10.0 L / n2
n2 = 10.0 L x 0.02 mol / 7.0 L
n2 = 0.0285 mol
no of moles we should add i s
0.0285 - 0.02
= 0.0086 mol
so to the intial mol we have to add 0.0086 mol of
option A is the correct answer
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