Suppose that the balanced chemical reaction for the complex was f_e^3+ (aq) + 6S

Question

Suppose that the balanced chemical reaction for the complex was f_e^3+ (aq) + 6SCN^- (aq) rightarrow Fe(scn)_6^3-(aq). Write the expression for Kc. K_c = [F_e (s c N_6)^3]/[Fe^2t][ScN^-]^6 Using the stoichiometric of the reaction given in Question I to relate [Fe^3+] to (Fe(SCN)_6^3-]. show the equation used to calculate [Fe^3+)_E (similar to what appears in Equation 3). In this case. Equation 2 would be: lFc(SCN)_6^3-]_E = a_e/A_std x [Fe(SCN)_6^3-]_sad Using the stoichiometric of the reaction given in Question 1 to relate [SCN-] to [Fe(SCN)_6^3-], show the equation that would be used to calculate [SCN^-]_e (similar to what appears in Equation 4). Using A_E -0 0140, A =1.232, [Fe(SCN)_6^3-] = 0 0350 M, [Fe^3+]_1 =0.0050 m, [SCN^-]_1 = 0.302M. and the reaction stoichiometry from Question 1, calculate Kc.

Explanation / Answer

1. Kc = [Fe(SCN)63-]/[Fe3+][SCN-]6

2. Fe3+ =[ AE]/ [Astd] * [Fe(SCN)63-]/[SCN-]6

3.   [SCN-]E6 =[ AE]/ [Astd] * [Fe(SCN)63-]/[Fe3+]E

4. Kc = [ AE]/ [Astd] * [Fe(SCN)63-]/[Fe3+][SCN-]6

   Kc = 0.0140/1.232 * (0.0350)/(0.0050)(0.302)

  Kc = 0.2634

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