3. 9 points total) In a study of the codominant blood typing alleles, L M and L
ID: 102055 • Letter: 3
Question
3. 9 points total) In a study of the codominant blood typing alleles, LM and LN in a population of mice on Island A, it was found that there were 165 MM blood types 870 MN and 965 NN blood types.
A. (2 points) Give the values for p and q in this population, showing your calculations.
B. (2 points) Is the population in Hardy-Weinberg equilibrium? How do you know?
A neighbouring population on Island B, has LM frequency = 0.8 and LN = 0.2.
C. The two populations have never “met” before, but then 200 mice from population B travel to island A by accident on a floating raft of logs and plant material. What will the allele frequencies in this new merged population be? (2 points)
D. Suppose that positive assortative mating takes place in this new population and mice now only mate with mice of the same MN blood type as themselves. What will the allele frequencies be after one generation of this assortative mating? (3 points)
Explanation / Answer
given, MM=165; MN=870, NN=965; total =2000
Answer [A] Frequency of allele M= (MM+ MN/2) / TOTAL= (165+ 435)/2000= 600/2000=0.3
Frequency of allele N= (NN+ MN/2) / TOTAL= (965+870/2) /2000=1400/2000= 0.7
therefore, p=0.3 and q= 0.7
Answer [B] yes, popuation is in hardy weinberg equibrium because according to hardy weinberg law, p+q=1, here we calculated, p= 0.3 and q= 0.7 that sums up to 1.
Answer [C] Given, LM=0.8 and LN= 0.2 and 200 individuals are added in existing population then,
allelic frequencies of new population would b the same as of original population because hardy weinberg law assumes no imigration or emigration have effect on the population.
Answer [D] to maintain hardy weiberg equillibrium in a population random mating must occur, failing which can lead to disequillibrium in population which is seen in natural selection or genetic drift.
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