#1 For 470.0 mL of a buffer solution that is 0.160 M in HC2H3O2 and 0.150 M in N

Question

#1 For 470.0 mL of a buffer solution that is 0.160 M in HC2H3O2 and 0.150 M in NaC2H3O2, calculate the initial pH and the final pH after adding 0.020 mol of HCl.

Find

pHinitial, pHfinal =

#2   For 470.0 mL of a buffer solution that is 0.150 M in CH3CH2NH2 and 0.140 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.020 mol of HCl

Find: pHinitial, pHfinal =

pHinitial, pHfinal =

#2   For 470.0 mL of a buffer solution that is 0.150 M in CH3CH2NH2 and 0.140 M in CH3CH2NH3Cl, calculate the initial pH and the final pH after adding 0.020 mol of HCl

Explanation / Answer

Initial pH

pH = pKa + log(base/acid)

     = 4.75 + log(0.15/0.16)

     = 4.722

After 0.02 mol HCl is added

pH = 4.75 + log[(0.15 M x 0.470 L - 0.02 mol)/0.470)/(0.16 M x 0.470 L + 0.02 mol)/0.470)]

      = 4.474

change in pH = 4.722 - 4.474 = 0.248

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