Print Calculator Periodic Table Question 29 of 29 Map General Chemistry 4th Edit

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Print Calculator Periodic Table Question 29 of 29 Map General Chemistry 4th Edition University Science Books presented by Sapling Learning Consider the following Gibbs energies at 25 C. Substance AG (k J. mol Ag (aq) 77.1 Cl (aq 131.2 -109.8 AgCl(s Br (aq) 04.0 96.9 AgBr(s) Calculate AGron for the dissolution of AgCl(s). (b) Calculate the solubility product constant of Agor. Number Number J. mol (c) Calculate AG non for the dissolution of AgBr(s). (d) Calculate the solubility-product constant of AgBr Number Number K- C kJ mol

Explanation / Answer

(a) Dissociation of AgCl(s)

dGorxn = dGof(products) - dGof(reactants)

             = (77.1 - 131.2) - (- 109.8) = 55.7 kJ/mol

(b) Solubility product constant K for AgCl

dGorxn = -RTlnK

55700 = -8.314 x 298 lnK

K = 1.723 x 10^-10

(c) Dissolution of AgBr(s)

dGorxn = dGof(products) - dGof(reactants)

             = (77.1 - 104) - (- 96.9) = 70 kJ/mol

(d) Solubility product constant K for AgBr

dGorxn = -RTlnK

70000 = -8.314 x 298 lnK

K = 5.366 x 10^-13

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