1) In the electrochemical voltaic cell using the reaction, Zn(s) + Cu 2+ (aq) Zn
ID: 1019361 • Letter: 1
Question
1) In the electrochemical voltaic cell using the reaction, Zn(s) + Cu2+(aq) Zn2+(aq) + Cu(s), match the correct 1/2 reaction that occurs at the anode and cathode.
1/2 reaction occuring at the anode
1/2 Reaction occuring at the cathode
Cu2+(aq) + 2e Cu(s)
Cu(s) + 2e Cu2+(aq)
Zn2+(aq) + 2e Zn(s)
Cu2+(aq) Cu(s) + 2e
Zn(s) Zn2+(aq) + 2e
Zn(s) + 2e Zn2+(aq)
2)Using the reduction potentials table in the notes/book, which of the following is the best oxidizing agent?
Cl2
I2
Cl-
I-
- A. B. C. D. E. F.1/2 reaction occuring at the anode
- A. B. C. D. E. F.1/2 Reaction occuring at the cathode
A.Cu2+(aq) + 2e Cu(s)
B.Cu(s) + 2e Cu2+(aq)
C.Zn2+(aq) + 2e Zn(s)
D.Cu2+(aq) Cu(s) + 2e
E.Zn(s) Zn2+(aq) + 2e
F.Zn(s) + 2e Zn2+(aq)
Explanation / Answer
1/2 reaction occuring at the anode :
E. Zn(s) Zn2+(aq) + 2e
1/2 Reaction occuring at the cathode:
A. Cu2+(aq) + 2e Cu(s)
2) reduction potential of Cl2 = +1.36 V
reduction potential of I2 = 0.54 V
higher the reduction potential , stronger the oxidising agent.
so that,
answer: Cl2
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