You\'ll use a multimeter to measure voltage, current, and/or resistance of a sim

Question

You'll use a multimeter to measure voltage, current, and/or resistance of a simple circuit consisting of a resistor and a power source.

More voltage should produce more current. Determine or verify exactly how this relationship works. Estimate the errors in all measurements so that you can know how closely to your prediction of behavior the results are.

People often use water flow as an model for electrical flow. Which electrical quantity do you think best fits voltage for the water model of electricity?

People often use water flow as an model for electrical flow. Which electrical quantity do you think best fits electric current for the water model of electricity?

How would you expect electrical current to change in a resistor when the voltage across the resistor increases?

If you keep the voltage across a resistor constant and reduce the resistance of the resistor, how do you expect the current through the resistor to change?

If you keep the voltage across a resistor constant and reduce the conductance of the resistor, how do you expect the current through the resistor to change?

If you replace one resistor in a circuit with two connected end-to-end (in series) and keep the same voltage across them, how do you think that the current will change?

If you replace one resistor in a circuit with two with both ends connected together (in parallel) and keep the same voltage across them, how do you think that the current will change?

Suppose that you arrange a circuit so that the current through a resistor remains constant. If you reduce the resistance of the resistor, what do you expect to happen to the voltage across the resistor?

Explanation / Answer

1.electric potential or voltage difference is analogous to the pressure difference. Hence Water preessure is correct.

2. Current is analogous Volumetric flow rate

3. The relation between voltage and current is given by V= iR

since Voltage is constant IR= Constant , I= Constant/R

Resitance is reduced, current increases

4. since V= iR   r= Resistance C= conductance = 1/R

V= i/C.

VC= i or voltage is proportional to current

So when voltage is curent decrease in conductance decreases the current

5. when resistances are connected in series, R= R1+R2 for resistances in series and resistance has increased.

V= iR

Siince V is constant, R is increased, i will have to decrease to Keep V constant.

6.when resistance are connected in parallel, 1/R= 1/R1+1/R2

R decreases and hence i will have to increase to keep V constant.

7. V= iR

i= V/R When Resistance is reduced, Voltage also gets reduced for keeping the i constant.

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