At a certain temperature, the Kp for the decompositon of H2S is 0.706 atm. Inita

Question

At a certain temperature, the Kp for the decompositon of H2S is 0.706 atm. Initally, only H2S is present at a pressure of 0.129 atm in a closed container. What is the total pressure in the container at equilibrium?

Question 8 of 15 Sapling Learning At a certain temperature, the K, for the decompositon of H2S is 0.706 atm Initally, only H2S is present at a pressure of 0.129 atm in a closed container. What is the total pressure in the container at equilibrium? Number atm Previous 0 Check Answer Next Exit Hint

Explanation / Answer

          H2S ------> H2 + S

I        0.129        0      0

C     -x              +x    +x

E    0.129-x       +x    +x

Kp   = PH2 Ps/PH2S

0.706 = x*x/0.129-x

0.706     = x2 /0.129     x<<<<<0.129

x2     = 0.706*(0.129-x)

x      = 0.111

PH2S   = 0.129-x = 0.129-0.111 = 0.18atm

PH2   = x = 0.111atm

PS   = x = 0.111atm

total pressure = PH2S + PH2 + PS

                      = 0.18+ 0.111 + 0.111   = 0.402atm

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