need help balancing the cathode and anode A galvanic cell is powered by the foll

Question

need help balancing the cathode and anode

A galvanic cell is powered by the following redox reaction: 210 (aa) 12 H (aq) 10 Br (eq) Ir(s) 6 H20() 5 Br 2 Answer the following questions about this cell. If you need any electrochemical data be sure you get it from the ALEKS Data ta write a balanced equation for the half reaction that takes place at the 0 write a balanced equation for the half reaction that takes place at the L Calculate the cel woltage under standard conditions Round your answer to 2 decimal

Explanation / Answer

Balanced cathode reaction,

2IO3-(aq) + 12H+(aq) + 10e- ---> I2(s) + 6H2O(l)

Balanced anode reaction,

2Br- ----> Br2(l) + 2e-

Cell voltage Eo = 1.195 - 1.066 = 0.13 V

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.